# Day 2 {% embed url="" %} ## Part One You play several games and record the information from each game (your puzzle input). Each game is listed with its ID number (like the `11` in `Game 11: ...`) followed by a semicolon-separated list of subsets of cubes that were revealed from the bag (like `3 red, 5 green, 4 blue`). For example, the record of a few games might look like this: ``` Game 1: 3 blue, 4 red; 1 red, 2 green, 6 blue; 2 green Game 2: 1 blue, 2 green; 3 green, 4 blue, 1 red; 1 green, 1 blue Game 3: 8 green, 6 blue, 20 red; 5 blue, 4 red, 13 green; 5 green, 1 red Game 4: 1 green, 3 red, 6 blue; 3 green, 6 red; 3 green, 15 blue, 14 red Game 5: 6 red, 1 blue, 3 green; 2 blue, 1 red, 2 green ``` In game 1, three sets of cubes are revealed from the bag (and then put back again). The first set is 3 blue cubes and 4 red cubes; the second set is 1 red cube, 2 green cubes, and 6 blue cubes; the third set is only 2 green cubes. The Elf would first like to know which games would have been possible if the bag contained *only 12 red cubes, 13 green cubes, and 14 blue cubes*? In the example above, games 1, 2, and 5 would have been *possible* if the bag had been loaded with that configuration. However, game 3 would have been *impossible* because at one point the Elf showed you 20 red cubes at once; similarly, game 4 would also have been *impossible* because the Elf showed you 15 blue cubes at once. If you add up the IDs of the games that would have been possible, you get *`8`*. Determine which games would have been possible if the bag had been loaded with only 12 red cubes, 13 green cubes, and 14 blue cubes. *What is the sum of the IDs of those games?* {% code lineNumbers="true" %} ```python import re red = 12 green = 13 blue = 14 valid_games = [] for line in open("../test.txt", "r"): game_id = re.findall(r'Game\s(\d+):', line) is_red_valid = False is_green_valid = False is_blue_valid = False red_occurrences = re.findall(r'(\d+)\sred', line) for each in red_occurrences: if int(each) <= red: is_red_valid = True else: is_red_valid = False break green_occurrences = re.findall(r'(\d+)\sgreen', line) for each in green_occurrences: if int(each) <= green: is_green_valid = True else: is_green_valid = False break blue_occurrences = re.findall(r'(\d+)\sblue', line) for each in blue_occurrences: if int(each) <= blue: is_blue_valid = True else: is_blue_valid = False break if is_red_valid and is_green_valid and is_blue_valid: valid_games.append(int(game_id[0])) print(sum(valid_games)) ``` {% endcode %} *** ## Part Two As you continue your walk, the Elf poses a second question: in each game you played, what is the *fewest number of cubes of each color* that could have been in the bag to make the game possible? Again consider the example games from earlier: ``` Game 1: 3 blue, 4 red; 1 red, 2 green, 6 blue; 2 green Game 2: 1 blue, 2 green; 3 green, 4 blue, 1 red; 1 green, 1 blue Game 3: 8 green, 6 blue, 20 red; 5 blue, 4 red, 13 green; 5 green, 1 red Game 4: 1 green, 3 red, 6 blue; 3 green, 6 red; 3 green, 15 blue, 14 red Game 5: 6 red, 1 blue, 3 green; 2 blue, 1 red, 2 green ``` * In game 1, the game could have been played with as few as 4 red, 2 green, and 6 blue cubes. If any color had even one fewer cube, the game would have been impossible. * Game 2 could have been played with a minimum of 1 red, 3 green, and 4 blue cubes. * Game 3 must have been played with at least 20 red, 13 green, and 6 blue cubes. * Game 4 required at least 14 red, 3 green, and 15 blue cubes. * Game 5 needed no fewer than 6 red, 3 green, and 2 blue cubes in the bag. The *power* of a set of cubes is equal to the numbers of red, green, and blue cubes multiplied together. The power of the minimum set of cubes in game 1 is `48`. In games 2-5 it was `12`, `1560`, `630`, and `36`, respectively. Adding up these five powers produces the sum *`2286`*. For each game, find the minimum set of cubes that must have been present. *What is the sum of the power of these sets?* {% code lineNumbers="true" %} ```python import re powers = [] for line in open("../test.txt", "r"): red_occurrences = sorted(list(map(int, re.findall(r'(\d+)\sred', line)))) green_occurrences = sorted(list(map(int, re.findall(r'(\d+)\sgreen', line)))) blue_occurrences = sorted(list(map(int, re.findall(r'(\d+)\sblue', line)))) powers.append(red_occurrences[-1] * green_occurrences[-1] * blue_occurrences[-1]) print(sum(powers)) ``` {% endcode %} --- # Agent Instructions: Querying This Documentation If you need additional information that is not directly available in this page, you can query the documentation dynamically by asking a question. Perform an HTTP GET request on the current page URL with the `ask` query parameter: ``` GET https://thamizhiniyancs.gitbook.io/writeups/advent-of-code/2023/day-2.md?ask= ``` The question should be specific, self-contained, and written in natural language. The response will contain a direct answer to the question and relevant excerpts and sources from the documentation. Use this mechanism when the answer is not explicitly present in the current page, you need clarification or additional context, or you want to retrieve related documentation sections.